PYTHON func_get_args

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Python replacement for PHP's func_get_args [ edit | history ]
def foo(*args): # just use "*" to collect all remaining arguments into a tuple
    numargs = len(args)
    print "Number of arguments: %s<br />" % numargs
    if numargs >= 2:
        print "Second argument is: %s<br />" % args[1]
    for i, x in enumerate(args):
        print "Argument %d is: %s<br />" % (i, x)

PHP func_get_args

PHP original manual for func_get_args [ show | php.net ]

func_get_args

(PHP 4, PHP 5)

func_get_argsReturns an array comprising a function's argument list

Description

array func_get_args ( void )

Gets an array of the function's argument list.

This function may be used in conjunction with func_get_arg() and func_num_args() to allow user-defined functions to accept variable-length argument lists.

Return Values

Returns an array in which each element is a copy of the corresponding member of the current user-defined function's argument list.

Changelog

Version Description
5.3.0 This function can now be used in parameter lists.

Errors/Exceptions

Generates a warning if called from outside of a user-defined function.

Examples

Example #1 func_get_args() example

<?php
function foo()
{
    
$numargs func_num_args();
    echo 
"Number of arguments: $numargs<br />\n";
    if (
$numargs >= 2) {
        echo 
"Second argument is: " func_get_arg(1) . "<br />\n";
    }
    
$arg_list func_get_args();
    for (
$i 0$i $numargs$i++) {
        echo 
"Argument $i is: " $arg_list[$i] . "<br />\n";
    }
}

foo(123);
?>

Notes

Note: Because this function depends on the current scope to determine parameter details, it cannot be used as a function parameter. If this value must be passed, the results should be assigned to a variable, and that variable should be passed.

Note: This function returns a copy of the passed arguments only, and does not account for default (non-passed) arguments.

See Also