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PYTHON imagecopy
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Python replacement for PHP's imagecopy
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def imagecopy (dst_im, src_im, dst_x, dst_y, src_x, src_y, src_w, src_h):
src_im_crop = src_im.crop((src_x, src_y, src_x + src_w, src_y + src_h)) dst_im.paste(src_im_crop, (dst_x, dst_y)) return True imagecopy(PHP 4, PHP 5) imagecopy — Copy part of an image Description
bool imagecopy
( resource $dst_im
, resource $src_im
, int $dst_x
, int $dst_y
, int $src_x
, int $src_y
, int $src_w
, int $src_h
)
Copy a part of src_im onto dst_im starting at the x,y coordinates src_x , src_y with a width of src_w and a height of src_h . The portion defined will be copied onto the x,y coordinates, dst_x and dst_y . Parameters
Return ValuesReturns TRUE on success or FALSE on failure. Examples
Example #1 Cropping the PHP.net logo
<?phpThe above example will output something similar to: ![]()
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