PYTHON imagecreatefromjpeg

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PHP imagecreatefromjpeg

PHP original manual for imagecreatefromjpeg [ show | php.net ]

imagecreatefromjpeg

(PHP 4, PHP 5)

imagecreatefromjpegCreate a new image from file or URL

Description

resource imagecreatefromjpeg ( string $filename )

imagecreatefromjpeg() returns an image identifier representing the image obtained from the given filename.

Tip

A URL can be used as a filename with this function if the fopen wrappers have been enabled. See fopen() for more details on how to specify the filename and List of Supported Protocols/Wrappers for a list of supported URL protocols.

Parameters

filename

Path to the JPEG image.

Return Values

Returns an image resource identifier on success, FALSE on errors.

Examples

Example #1 Example to handle an error during loading of a JPEG

<?php
function LoadJpeg($imgname)
{
    
/* Attempt to open */
    
$im = @imagecreatefromjpeg($imgname);

    
/* See if it failed */
    
if(!$im)
    {
        
/* Create a black image */
        
$im  imagecreatetruecolor(15030);
        
$bgc imagecolorallocate($im255255255);
        
$tc  imagecolorallocate($im000);

        
imagefilledrectangle($im0015030$bgc);

        
/* Output an error message */
        
imagestring($im155'Error loading ' $imgname$tc);
    }

    return 
$im;
}

header('Content-Type: image/jpeg');

$img LoadJpeg('bogus.image');

imagejpeg($img);
imagedestroy($img);
?>

The above example will output something similar to:

Notes

Note: JPEG support is only available if PHP was compiled against GD-1.8 or later.

Warning

Windows versions of PHP prior to PHP 4.3.0 do not support access of remote files via this function, even if allow_url_fopen is enabled.