PYTHON parse_url

is this article helpful?
Python replacement for PHP's parse_url [ edit | history ]
import urlparse
print urlparse.urlparse('[url][/url]')
import urllib.parse
print urllib.parse.urlparse('[url][/url]')

PHP parse_url

PHP original manual for parse_url [ show | ]


(PHP 4, PHP 5)

parse_urlParse a URL and return its components


mixed parse_url ( string $url [, int $component= -1 ] )

This function parses a URL and returns an associative array containing any of the various components of the URL that are present.

This function is not meant to validate the given URL, it only breaks it up into the above listed parts. Partial URLs are also accepted, parse_url() tries its best to parse them correctly.



The URL to parse. Invalid characters are replaced by _.


Specify one of PHP_URL_SCHEME, PHP_URL_HOST, PHP_URL_PORT, PHP_URL_USER, PHP_URL_PASS, PHP_URL_PATH, PHP_URL_QUERY or PHP_URL_FRAGMENT to retrieve just a specific URL component as a string.

Return Values

On seriously malformed URLs, parse_url() may return FALSE and emit a E_WARNING. Otherwise an associative array is returned, whose components may be (at least one):

  • scheme - e.g. http
  • host
  • port
  • user
  • pass
  • path
  • query - after the question mark ?
  • fragment - after the hashmark #

If the component parameter is specified a string is returned instead of an array.


Version Description
5.1.2 Added the component parameter


Example #1 A parse_url() example




The above example will output:

    [scheme] => http
    [host] => hostname
    [user] => username
    [pass] => password
    [path] => /path
    [query] => arg=value
    [fragment] => anchor


Note: This function doesn't work with relative URLs.

Note: This function is intended specifically for the purpose of parsing URLs and not URIs. However, to comply with PHP's backwards compatibility requirements it makes an exception for the file:// scheme where triple slashes (file:///...) are allowed. For any other scheme this is invalid.

See Also